Issue
Assume I have the following models:
class Tag(Model):
name = CharField()
class Book(Model):
title = CharField()
tags = ManyToManyField(Tag)
Now suppose I have 3 books, and each book has 3 tags. Some of the tags might be the same for some of the books, it doesn't matter.
Book 1 (Tags = "tag1", "tag2", "tag3")
Book 2 (Tags = "tag1", "tag4", "tag5")
Book 3 (Tags = "tag4", "tag5", "tag6")
How can I count all non-distinct tags in a Django ORM query so that I get 9 as a result?
Solution
You can count with:
Book.tags.through.objects.count()
This will count the number of tags for all Book
s. If you have a set of Book
s, you can count with:
Tag.objects.filter(book__in=[1, 2, 3]).count()
Answered By - Willem Van Onsem
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