[FIXED] How to get boolean result of a typecasting in python?

Issue

My expectation is if typecasting is successful I need to get 'True'. If the typecasting is not successful, I need to get 'False'.

Let's say there is a list.

details_list = ["ramji",10, -12, "muthu", 20]

I want to check the value in each index whether it is an integer. If the value in each index is convertible to int, I should get 'True'. Otherwise, 'False'

Below is the code I tried.

def get_first_value(number_list):
    counter = 0
    while counter < len(number_list):
        if int(number_list[counter]):   # Getting error at this line.
            counter = counter + 1
        else:
            return False

    return number_list[0]    

details_list = ["ramji",10, -12, "muthu", 20]
status = get_first_value(details_list)
print(status)

I get an error which is...

if bool(int(number_list[counter])):

ValueError: invalid literal for int() with base 10: 'ramji'

Please help me.

Solution

You can try/except:

try:
    int_value = int(number_list[counter])
    counter = counter + 1
except ValueError:
    return False

Or you can use isinstance:

is_int = isinstance(number_list[counter], int)

Answered By - Lorenzo Bonetti