Issue
I have a project based on django (3.2.10) and sentry-sdk (1.16.0) There is my sentry-init file:
from os import getenv
SENTRY_URL = getenv('SENTRY_URL')
if SENTRY_URL:
from sentry_sdk import init
from sentry_sdk.integrations.django import DjangoIntegration
from sentry_sdk.integrations.redis import RedisIntegration
from sentry_sdk.integrations.celery import CeleryIntegration
init(
dsn=SENTRY_URL,
integrations=[DjangoIntegration(), RedisIntegration(), CeleryIntegration()],
traces_sample_rate=1.0,
send_default_pii=True,
debug=True,
)
I have a CustomError inherited from Exception
Every time I raise the CustomError sentry-sdk sends it to the dsn-url.
I want to ignore some class of error or something like this. How can I do this?
Solution
You can pass a function that filters the errors to be sent:
from os import getenv
SENTRY_URL = getenv('SENTRY_URL')
if SENTRY_URL:
from sentry_sdk import init
from sentry_sdk.integrations.django import DjangoIntegration
from sentry_sdk.integrations.redis import RedisIntegration
from sentry_sdk.integrations.celery import CeleryIntegration
def before_send(event, hint):
if 'exc_info' in hint:
exc_type, exc_value, tb = hint['exc_info']
if isinstance(exc_value, CustomError): # Replace CustomError with your custom error
return None
return event
init(
dsn=SENTRY_URL,
integrations=[DjangoIntegration(), RedisIntegration(), CeleryIntegration()],
traces_sample_rate=1.0,
send_default_pii=True,
debug=True,
before_send=before_send
)
You can find more info in the documentation.
Answered By - RedWheelbarrow
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