Issue
I have an array like:
data=np.array([1,2,3,5,8,7,2,1,3,5,1,2,20])
I would like to mask an array indices with a step of 3. For an example I able to mask where the value of an array equal to 3.
import numpy as np
import numpy.ma as ma
x = np.array([1,2,3,5,8,7,2,1,3,5,1,2,20])
mx=ma.masked_values(x,3)
output:
[1 2 -- 5 8 7 2 1 -- 5 1 2 20]
Requirement: I need to mask the every 3nd Indices in an array.(step of 3)
Required Output:
[1,2,3,--,8,7,--,1,3,--,1,2,--]
Solution
Let us create a mask based on the indices of the array:
np.ma.masked_array(x, np.r_[1, 1:len(x)] % 3 == 0)
masked_array(data=[1, 2, 3, --, 8, 7, --, 1, 3, --, 1, 2, --],
mask=[False, False, False, True, False, False, True, False,
False, True, False, False, True],
fill_value=999999)
Answered By - Shubham Sharma
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