[FIXED] Pandas: map new column to existing column based on condition

Issue

I have a table like this:

id	q1_score	q2_score	q3_score	q4_score	quarter
1	-0.77	-0.55	0.21	3.42	q1
2	-0.77	-0.55	0.21	3.42	q1
3	-0.77	-0.55	0.21	3.42	q2
4	-0.77	-0.55	0.21	3.42	q3
5	-0.77	-0.55	0.21	3.42	q4

I want to create a new column quarter_score based on the value of quarter.

1. If quarter==q1 then quarter_score=value from q1_score of that row.
2. If quarter==q2 then quarter_score=value from q2_score of that row.
3. so forth ...

My code looks like this

mapper = {'q1': df['q1_score'], 'q2':df['q2_score'], 'q3': df['q3_score'], 'q4': df['q4_score']}
df['quarter_score'] = df['quarter'].map(mapper)

but it does not take single value, it takes whole rows for that column for each row.

id	q1_score	q2_score	q3_score	q4_score	quarter	quarter_score
1	-0.77	-0.55	0.21	3.42	q1	0 -0.77 1 -0.77 2 -0.77
2	-0.77	-0.55	0.21	3.42	q1	0 -0.77 1 -0.77 2 -0.77
3	-0.77	-0.55	0.21	3.42	q2	0 -0.55 1 -0.55 2 -0.55
4	-0.77	-0.55	0.21	3.42	q3	0 0.21 1 0.21 2 0.21
5	-0.77	-0.55	0.21	3.42	q4	0 3.42 1 3.42 2 3.42

My final output should be like this below.

id	q1_score	q2_score	q3_score	q4_score	quarter	quarter_score
1	-0.77	-0.55	0.21	3.42	q1	-0.77
2	-0.77	-0.55	0.21	3.42	q1	-0.77
3	-0.77	-0.55	0.21	3.42	q2	-0.55
4	-0.77	-0.55	0.21	3.42	q3	0.21
5	-0.77	-0.55	0.21	3.42	q4	3.42

Solution

Try:

df["quarter_score"] = df.apply(lambda x: x[x["quarter"] + "_score"], axis=1)
print(df)

Prints:

   id  q1_score  q2_score  q3_score  q4_score quarter  quarter_score
0   1     -0.77     -0.55      0.21      3.42      q1          -0.77
1   2     -0.77     -0.55      0.21      3.42      q1          -0.77
2   3     -0.77     -0.55      0.21      3.42      q2          -0.55
3   4     -0.77     -0.55      0.21      3.42      q3           0.21
4   5     -0.77     -0.55      0.21      3.42      q4           3.42

Answered By - Andrej Kesely