[FIXED] How to modify/clear/delete a QWidget from a QGridLayout ? - Python, PyQt

Issue

I wish to have a QGridLayout containing some informations that can be dynamicaaly changed. However, as it is, it will only superimpose the different informations on top of the previous one instead of replacing it. Surprisingly I couldn't find a method to remove or clean or such a widget from a grid. So what, can't it be dynamically changed ?...

Here is an example of code :

import sys

from PyQt5.QtWidgets import (
    QApplication,
    QGridLayout,
    QPushButton,
    QWidget,
    QLabel
)

class Window(QWidget):
    def __init__(self):
        super().__init__()
        self.setWindowTitle("QGridLayout Example")
        # Create a QGridLayout instance
        self.buttonA = QPushButton("A")
        self.buttonB = QPushButton("B")
        self.layout = QGridLayout()
        # Add widgets to the layout
        self.layout.addWidget(self.buttonA, 0, 1)
        self.layout.addWidget(self.buttonB, 0, 2)
        self.layout.addWidget(QPushButton("C"), 1, 0)
        self.layout.addWidget(QPushButton("D"), 1, 1)
        self.layout.addWidget(QPushButton("E"), 1, 2)
        self.layout.addWidget(QPushButton("F"), 2, 0)
        self.layout.addWidget(QPushButton("G"), 2, 1)
        self.layout.addWidget(QPushButton("H"), 2, 2)
        # Set the layout on the application's window
        self.setLayout(self.layout)

        
        self.buttonA.clicked.connect(self.change_label)
        self.buttonB.clicked.connect(self.change_label2)
        
    def change_label(self):
        self.label = QLabel("Hello")
    self.layout.addWidget(self.label, 0, 0)
        
    def change_label2(self):
        self.label = QLabel("Bonjour")
    self.layout.addWidget(self.label, 0, 0)
        
if __name__ == "__main__":
    app = QApplication(sys.argv)
    window = Window()
    window.show()
    sys.exit(app.exec_())

When one clicks on button A, I want to have displayed in box (0,0) "Hello". Then if one clicks on button B, I want to replace the text "Hello" with "Bonjour". However I can only have one text on top of the other which is obviously hardly readable then.

Can someone help me ?

Solution

Just use this code:

import sys

from PyQt5.QtWidgets import (
    QApplication,
    QGridLayout,
    QPushButton,
    QWidget,
    QLabel
)

class Window(QWidget):
    def __init__(self):
        super().__init__()
        self.setWindowTitle("QGridLayout Example")
        # Create a QGridLayout instance
        self.label = QLabel("Show text here")

        self.buttonA = QPushButton("A")
        self.buttonB = QPushButton("B")
        self.layout = QGridLayout()
        # Add widgets to the layout
        self.layout.addWidget(self.label, 0, 0)
        self.layout.addWidget(self.buttonA, 0, 1)
        self.layout.addWidget(self.buttonB, 0, 2)
        self.layout.addWidget(QPushButton("C"), 1, 0)
        self.layout.addWidget(QPushButton("D"), 1, 1)
        self.layout.addWidget(QPushButton("E"), 1, 2)
        self.layout.addWidget(QPushButton("F"), 2, 0)
        self.layout.addWidget(QPushButton("G"), 2, 1)
        self.layout.addWidget(QPushButton("H"), 2, 2)
        # Set the layout on the application's window
        self.setLayout(self.layout)

        
        self.buttonA.clicked.connect(self.change_label)
        self.buttonB.clicked.connect(self.change_label2)
        
    def change_label(self):
        self.label.setText("Hello")
        
    def change_label2(self):
        self.label.setText("Bonjour")
        
if __name__ == "__main__":
    app = QApplication(sys.argv)
    window = Window()
    window.show()
    sys.exit(app.exec_())

Answered By - OualidSai