[FIXED] Mapping two rows to one row in pandas

Issue

I have a dataframe a with 14 rows and another dataframe comp1sum with 7 rows. a has date column for 7 days in 12hr interval. So that makes it 14 rows. Also, comp1sum has a column with 7 days.

This is the comp1sum dataframe

And this is the a dataframe

I want to map 2 rows of a dataframe to single rows of comp1sum dataframe. So, that one day of dataframe a is mapped to one day of comp1sum dataframe.

I have the following code for that

j=0
for i in range(0,7):
    a.loc[i,'comp1_sum'] = comp_sum.iloc[j]['comp1sum']
    a.loc[i,'comp2_sum'] = comp_sum.iloc[j]['comp2sum']
    j=j+1

And its output is

      dt_truncated         comp1_sum
3   2015-02-01 00:00:00     142.0
10  2015-02-01 12:00:00     144.0
12  2015-02-03 00:00:00     145.0
2   2015-02-05 00:00:00     141.0
14  2015-02-05 12:00:00     NaN

The code is mapping the days from comp1sum based on index of a and not based on dates of a. I want 2015-02-01 00:00:00 to have the values 139.0 and 2015-02-02 00:00:00 to have the value 140.0 and so on such that increasing dates have increasing values.

I am not able to map in such a way. please help.

---

Edit1- As per @Ssayan answer, I am getting this error-

---------------------------------------------------------------------------
IndexError                                Traceback (most recent call last)
<ipython-input-255-77e55efca5f9> in <module>
      3 # use the sorted index to iterate through the sorted dataframe
      4 for i, idx in enumerate(a.index):
----> 5     a.loc[idx, 'comp1_sum'] = b.iloc[i//2]['comp1sum']
      6     a.loc[idx,'comp2_sum'] = b.iloc[i//2]['comp2sum']

IndexError: single positional indexer is out-of-bounds

Solution

Your issue is that your DataFrame a is not sorted by date so the index 0 does not match the earliest date. When you use loc it uses the value of the index, not the order in which the table is, so even with sorting the DataFrame the issue remains.

One way out is to sort the DataFrame a by date and then to use the sorted index to apply the value in the order you need.

# sort the dataframe by date
a = a.sort_values("dt_truncated")
# use the sorted index to iterate through the sorted dataframe
for i, idx in enumerate(a.index):
    a.loc[idx, 'val_1'] = b.iloc[i//2]['val1']
    a.loc[idx,'val_2'] = b.iloc[i//2]['val2']

Answered By - Ssayan