Issue
I have two numpy arrays and I am trying to divide one with the other and at the same time, I want to make sure that the entries where the divisor is 0, should just be replaced with 0.
So, I do something like:
log_norm_images = np.where(b_0 > 0, np.divide(diff_images, b_0), 0)
This gives me a run time warning of:
RuntimeWarning: invalid value encountered in true_divide
Now, I wanted to see what was going on and I did the following:
xx = np.isfinite(diff_images)
print (xx[xx == False])
xx = np.isfinite(b_0)
print (xx[xx == False])
However, both of these return empty arrays meaning that all the values in the arrays are finite. So, I am not sure where the invalid value is coming from. I am assuming checking b_0 > 0 in the np.where function takes care of the divide by 0.
The shape of the two arrays are (96, 96, 55, 64) and (96, 96, 55, 1)
Solution
You may have a NAN
, INF
, or NINF
floating around somewhere. Try this:
np.isfinite(diff_images).all()
np.isfinite(b_0).all()
If one or both of those returns False
, that's likely the cause of the runtime error.
Answered By - rchang
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