[FIXED] Set rows in Python 2D array to another row without Numpy?

Issue

I want to "set" the values of a row of a Python nested list to another row without using NumPy.

I have a sample list:

lst = [[0, 0, 1],
       [0, 2, 3],
       [5, 2, 3]]

I want to make row 1 to row 2, row 2 to row 3, and row 3 to row 1. My desired output is:

lst = [[0, 2, 3],
       [5, 2, 3],
       [0, 0, 1]]

How can I do this without using Numpy?

I tried to do something like arr[[0, 1]] = arr[[1, 0]] but it gives the error 'NoneType' object is not subscriptable.

Solution

One very straightforward way:

arr = [arr[-1], *arr[:-1]]

Or another way to achieve the same:

arr = [arr[-1]] + arr[:-1]

arr[-1] is the last element of the array. And arr[:-1] is everything up to the last element of the array.

The first solution builds a new list and adds the last element first and then all the other elements. The second one constructs a list with only the last element and then extends it with the list containing the rest.

Note: naming your list an array doesn't make it one. Although you can access a list of lists like arr[i1][i2], it's still just a list of lists. Look at the array documentation for Python's actual array.

The solution user @MadPhysicist provided comes down to the second solution provided here, since [arr[-1]] == arr[-1:]

Answered By - Grismar