[FIXED] Django, render with link or remove template dirs when render in view

Issue

hai i am newbie in django and sorry for grammar mistake first i have some project to upload file extension .html to AWS S3, so in views.py i want to render a link i've already uploaded to AWS S3. ex: render(request, 'somelink.com', context) , it possible? or any other solution? and also i want to send context parameters

why i not using media_url upload to local? cause i have limited disk, and other problem when i do production i cant load media_url, ignore this case, cause i already try many solution

Solution

Assuming that you want to render it server side, you will need to fetch the template (the .html file) and render it. You can do it using the requests library to fetch the url template. And the Django template render engine to render the context: https://docs.djangoproject.com/en/4.1/ref/templates/api/#rendering-a-context

import requests
from django.template import Template, Context

template = requests.get('somelink.com').content
t = Template(template)
c = Context(context)
return HttpResponse(t.render(c))

Notes:

1. It can worse the response time from your server.
2. As you are concerned about space, you can try to use a front-end solution to render data from your server via API.

Hope it can help you.

Answered By - JoVi