[FIXED] Function with another function as an optional argument

Issue

I'm trying to write a function that takes another function as an optional argument. I'm a little stuck (and confused) with the syntax. I want func2 to be an optional argument. So I only want it to work when I call it in func1. I want it to work as a filter function for when I have more complex file patterns. glob.glob(files + '/*')can give all the files in the directories specified. (glob.glob(path + '/' + file_name + '*')) can give more complex patterns, I'm just not sure how to implement it as an optional function argument. any help would be much appreciated!

import glob

def func1(dirs, func2):

    if type(dirs) == list:
        for files in dirs:
            files = glob.glob(files + '/*')
            print(files) # prints all of the file names in each directory given
            if func2:
                func2(file_name)          



def func2(file_name):
    if file_name in files:
        print(file_name)
        # (glob.glob(path + '/' + file_name + '*'))

func1(['C:\path\to\files1\', 'C:\path\to\files2\'], func2('test2'))

For this example assume \files1 contains 'test1.txt' and 'test2.txt' and files2 containts 'test1.jpg' and 'test2.jpg'. I want func1 to print the the path for test2.txt and test1.jpg.

Solution

The only difference is how you pass the function. You're currently passing the return of func2('test2'), you should just pass func2. Also be sure to pass files to func2, otherwise that won't be defined.

import glob

def func1(dirs, func2, another_variable):

    if type(dirs) == list:
        for files in dirs:
            files = glob.glob(files + '/*')
            print(files) # prints all of the file names in each directory given
            if func2:
                func2(another_variable, files)          



def func2(file_name, files):
    if file_name in files:
        print(file_name)
        # (glob.glob(path + '/' + file_name + '*'))

func1(['C:\path\to\files1\', 'C:\path\to\files2\'], func2, 'test_2')

Answered By - Nathan