Issue
I create a script that covert YouTube video links into id's:
print(link_data.head)
I have 100 rows in 1 column
0 tSbA3J_enCA
1 jWOgDXnqxi8
2 uNZH7zlZ-b4
3 SgXwnKTHRdM
4 TuN_vVoEqf4
.. ...
96 SxSQ29eUyfo
97 dmPb-gZgaBk
98 fA1Jzm9fK38
99 HNdQ6yXQmLE
100 Z8FdzNwSC3c
How to assign thislink_data
to id_list_data
and make it return more than 50 results?
id_list_data =
results = youtube.videos().list(id = id_list_data, part ='snippet').execute()
for result in results.get('items', []):
print(result ['id'])
print(result ['snippet']['channelTitle'])
print(result ['snippet']['title'])
print(result ['snippet']['description'])
Solution
As YouTube Data API v3 Videos: list endpoint has a maxResults
of 50, you have to call youtube.videos().list(...)
with at most 50 id
s.
maxResults = 50
for i in range(ceil(len(link_data.head) / maxResults)):
id_list_data = link_data.head[i * maxResults:(i + 1) * maxResults]
results = youtube.videos().list(id = id_list_data, part ='snippet').execute()
for result in results.get('items', []):
print(result ['id'])
print(result ['snippet']['channelTitle'])
print(result ['snippet']['title'])
print(result ['snippet']['description'])
Answered By - Benjamin Loison
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