[FIXED] How to block unexpected arguments in a function with **kwargs?

Issue

For example:

def f2(**kwargs):
    b = kwargs.get('b',2)
    print(b)

def f():
    f2(c=2)

f()

What can I do to show an error when I put this c as an argument and only allow the variables with name b (what the function is expecting).

Solution

kwargs is given as a dictionary. You can validate in any way you want.

def f2(**kwargs):
    assert "c" not in kwargs
    b = kwargs.get('b',2)
    print(b)

def f():
    f2(c=2)

f()

Answered By - Kota Mori