Issue
I have the coordinates (xmin,xmax), (ymin,ymax), (zmin, zmax) of a cuboid which I want to be plotted (just all the edges)
How can I do that?
Solution
I copied some math from Wikipedia some while ago. This function gives you, the edges and vertices of a cube.
import numpy as np
def get_cube(limits=None):
"""get the vertices, edges, and faces of a cuboid defined by its limits
limits = np.array([[x_min, x_max],
[y_min, y_max],
[z_min, z_max]])
"""
v = np.array([[0, 0, 0], [0, 0, 1],
[0, 1, 0], [0, 1, 1],
[1, 0, 0], [1, 0, 1],
[1, 1, 0], [1, 1, 1]], dtype=int)
if limits is not None:
v = limits[np.arange(3)[np.newaxis, :].repeat(8, axis=0), v]
e = np.array([[0, 1], [0, 2], [0, 4],
[1, 3], [1, 5],
[2, 3], [2, 6],
[3, 7],
[4, 5], [4, 6],
[5, 7],
[6, 7]], dtype=int)
f = np.array([[0, 2, 3, 1],
[0, 4, 5, 1],
[0, 4, 6, 2],
[1, 5, 7, 3],
[2, 6, 7, 3],
[4, 6, 7, 5]], dtype=int)
return v, e, f
Then you can just loop over the edges to draw the cube in matplotlib.
limits = np.array([[-2, 1],
[-1, 1],
[0, 2]])
v, e, f = get_cube(limits)
from mpl_toolkits.mplot3d import Axes3D
from matplotlib import pyplot as plt
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
ax.plot(*v.T, marker='o', color='k', ls='')
for i, j in e:
ax.plot(*v[[i, j], :].T, color='r', ls='-')
Answered By - scleronomic
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