[FIXED] Python: OSError: [Errno 22] Invalid argument: wrong path (on Output seems that Python modify my path )

Issue

hella.

seems to be a wrong path on my Python code. But I test again and again, the path and the file are good: c:\Folder1\bebe.txt

See the error OSError: [Errno 22] Invalid argument: 'c:\\Folder1\x08ebe.txt'

Python modify my path ??! Can you help me? Also, you have the entire code HERE:

Solution

Your problem is most likely this line:

file_path = 'C:\Something\booh'

In a Python string literal, backslashes are used to introduce special characters. For example \n means a newline and \b means a backspace. To actually get a backslash, you have to type \\. A backslash followed by a character with no special meaning is left alone, so \S actually means \S (though relying on this is probably a bad idea).

You can either type your line like this

file_path = 'C:\\Something\\booh'

or use Pythons "raw string" syntax, which turns off the special meaning of backslashes, and type

file_path = r'C:\Something\booh'

Notice that when you do

s = '\\'

the string referred to by s actually contains a single backslash. For example, len(s) will be 1, and print(s) will print a single backslash.

Answered By - Ture Pålsson