Issue
I am using Javascript to send an asynchronous request to a Django View. The View is able to receive data from the POST request, but I can't seem to return a message to confirm that everything worked. I was expecting that xhttp.responseText
would contain the message Thankyou
, but it is empty.
The html part looks like this:
<textarea id="message"></textarea>
<input type="submit" value="Send" id="send_button onclick="submit_message()"/>
The javascript looks like this:
function submit_message(){
document.getElementById("send_button").value="Sent - Thankyou!";
message = document.getElementById("message").value
var xhttp = new XMLHttpRequest();
xhttp.open("POST", "/send-message");
xhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xhttp.send("csrfmiddlewaretoken={{ csrf_token }}&message="+message);
console.log('Sent POST request')
console.log(xhttp.responseText)
}
I was hoping that xhttp.responseText
would print Thankyou
to the console.
The Django View function looks like this:
def send_message(request):
message = request.POST.get('message')
print(message)
return HttpResponse('Thankyou')
The message
variable prints out as expected, but Thankyou
doesn't seem to be returned.
I am doing AJAX with JS for the first time, so I expect I've just misunderstood something simple.
--- EDIT --- I have it working, after following the suggestion and reading this https://developer.mozilla.org/en-US/docs/Web/Guide/AJAX/Getting_Started
After the line xhttp.send(... I have this function
xhttp.onreadystatechange = function handle_response(){
if (xhttp.readyState === XMLHttpRequest.DONE) {
// Everything is good, the response was received.
console.log('Things are good')
console.log(xhttp)
console.log(xhttp.response)
} else {
// Not ready yet.
console.log('Not ready')
}
}
It wasn't necessary to use JsonResponse, but I will give that a try as well.
Solution
I can only recommend to you, the usage of JsonResponse instead of HttpResponse for confirm your submit. Your problem I presume it is in JS, you need to confirm the server response, check this article for better understand of ajax requests https://developer.mozilla.org/es/docs/Web/Guide/AJAX/Getting_Started#segundo_paso_.e2.80.93_procesando_la_respuesta_del_servidor
if (xhttp.readyState == 4) {
// response received
console.log(xhttp.responseText)
} else {
// server not ready yet
console.log("Server not ready")
}
Answered By - Juan Gabriel Valdés Díaz
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