[FIXED] Delete elements from numpy arrays at the same position by using zip() and np.delete()

Issue

I got two 1D arrays of same length (it and l) and I want to delete the element y in l for l < ls and also delete element x in it at the same position. I tried:

for x, y in zip(it, l):
        if y < ls:
            np.delete(l,y)
            np.delete(it,x)

But it is not working and there is the Warning:

"DeprecationWarning: using a non-integer array as obj in delete will result in an error in the future" np.delete(l,y)

"DeprecationWarning: using a non-integer array as obj in delete will result in an error in the future np.delete(it,x)"

Solution

Here you have an example.

You have to indicate the index of the element that you want to remove :

import numpy as np

it = np.asarray(range(10))
l = np.asarray(range(10))

ls = 4
index = []
for i, y in enumerate(l):
        if y < ls:
            index.append(i)

l = np.delete(l, index)
it = np.delete(it, index)

Results :

(array([4, 5, 6, 7, 8, 9]), array([4, 5, 6, 7, 8, 9]))

Shorter version :

index = np.argwhere(l < ls)
l = np.delete(l, index)
it = np.delete(it, index)

Answered By - JP Marcel