Issue
I'm new to flask, and I'm trying to add print info to debug server side code. When launch my flask app with debug=True, i can't get any info print to console
I tried to use logging instead, but no success. So how to debug flask program with console.
@app.route('/getJSONResult', methods=['GET', 'POST'])
def getJSONResult():
if request.method == 'POST':
uut = request.form['uut']
notes = request.form['notes']
temperature = request.form['temperature']
logging.info("enter getJSONReuslt")
print('enter getJSONReuslt')
filter_by_query = {k: v for k, v in {
'uut': uut, 'notes': notes, 'temperature': temperature}.items() if v != ""}
s = session.query(UUT_TEST_INFO).filter_by(**filter_by_query).first()
return jsonify(s.serialize)
if __name__ == '__main__':
app.secret_key = ''.join(random.choice(
string.ascii_uppercase + string.digits) for x in range(32))
app.debug = True
app.run(host='127.0.0.1', port=5000)
> 127.0.0.1 - - [07/Jun/2017 15:20:48] "GET /qyer HTTP/1.1" 200 -
> 127.0.0.1 - - [07/Jun/2017 15:20:48] "GET /static/css/bootstrap.min.css HTTP/1.1" 200 -
> 127.0.0.1 - - [07/Jun/2017 15:20:48] "GET /static/js/bootstrap.min.js HTTP/1.1" 200 -
> 127.0.0.1 - - [07/Jun/2017 15:20:51] "GET /static/css/bootstrap.min.css.map HTTP/1.1" 200 -
> 127.0.0.1 - - [07/Jun/2017 15:21:58] "POST /getJSONResult HTTP/1.1" 500 -
I fixed server side 500 error issue, now request get 200 code, and console displays following info
$ python project.py
INFO:werkzeug: * Running on http://127.0.0.1:5000/ (Press CTRL+C to quit)
INFO:werkzeug: * Restarting with stat
WARNING:werkzeug: * Debugger is active!
INFO:werkzeug: * Debugger pin code: 158-624-607
INFO:werkzeug:127.0.0.1 - - [08/Jun/2017 11:33:33] "GET /qyer HTTP/1.1" 200 -
INFO:root:Enter getJSONResult
INFO:werkzeug:127.0.0.1 - - [08/Jun/2017 11:33:43] "POST /getJSONResult HTTP/1.1" 200 -
Still no info from print command
Solution
Try this and see if it helps:
For python2:
from __future__ import print_function
import sys
print('This is error output', file=sys.stderr)
print('This is standard output', file=sys.stdout)
For python3 you don't need to import from future print_function:
import sys
print('This is error output', file=sys.stderr)
print('This is standard output', file=sys.stdout)
See if it helps to print to console.
Answered By - Nurjan
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