Issue
Is there a substitute of np.random.normal()
? I am seeking a function which will provide me a fixed mean
and not vary with every run as shown below.
import numpy as np
mu, sigma = 50, 1.0 # mean and standard deviation
Nodes=220
r = np.random.normal(mu, sigma, Nodes)
print(r)
mean=np.mean(r)
print("mean =",mean)
Run 1 gives
mean = 49.957893448684665
Run 2 gives
mean = 50.13868428629214
Solution
You can use a seed to make the random numbers 'predictable'. This way you fix your random numbers and the mean will stay the same each time you run it. Even better, for everyone, the mean is now the same:
import numpy as np
mu, sigma = 50, 1.0 # mean and standard deviation
Nodes=220
np.random.seed(0)
r = np.random.normal(mu, sigma, Nodes)
mean=np.mean(r)
print("mean =",mean)
Returns: 50.07519566707803
Changing the value (seed value 0
in this case) will change your results
Answered By - T C Molenaar
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