Issue
I'm using the module openpyxl for Python and am trying to create a hyperlink that will take me to a different tab in the same Excel workbook. Doing something similar to the following creates the hyperlink; however, when I click on it, it tells me it can't open the file.
from openpyxl import Workbook
wb = Workbook()
first_sheet = wb.create_sheet(title='first')
second_sheet = wb.create_sheet(title='second')
first_sheet['A1'] = "hello"
second_sheet['B2'] = "goodbye"
link_from = first_sheet['A1']
link_to = second_sheet['B2'].value
link_from.hyperlink = link_to
wb.save("C:/somepath/workbook.xlsx")
I'm assuming the issue lies in the value of 'link_to'; however, I don't know what would need changed or what kind of path I would have to write.
I'm using Python 2.7.6 and Excel 2013.
Solution
Support for hyperlinks in openpyxl is currently extremely rudimentary and largely limited to reading the links in existing files.
Answered By - Charlie Clark
0 comments:
Post a Comment
Note: Only a member of this blog may post a comment.