Issue
For some reason using numpy's trapz
and scipy's cumtrapz
yields different solutions.
x = np.linspace(-2, 4, num=20)
y = (x)
y_int = integrate.cumtrapz(y, x, initial=0)
y_tr = np.trapz(y, x, axis = 0)
display(y_tr)
display(y_int)
The final value given by trapz
rule is twice that given by cumtrapz
.
-5.551115123125783e-17
array([ 0.00000000e+00, -3.98891967e-01, -7.53462604e-01, -1.06371191e+00,
-1.32963989e+00, -1.55124654e+00, -1.72853186e+00, -1.86149584e+00,
-1.95013850e+00, -1.99445983e+00, -1.99445983e+00, -1.95013850e+00,
-1.86149584e+00, -1.72853186e+00, -1.55124654e+00, -1.32963989e+00,
-1.06371191e+00, -7.53462604e-01, -3.98891967e-01, -2.77555756e-16])
Is there a reason for this?
Solution
It seems the reason is the way memory is allocated and floating operations are carried out.
Both -2.77555756e-16
and -5.551115123125783e-17
are essentially 0. Running the same code by changing the limit from -2
to 4
gives the correct answer:
x = np.linspace(-2, 4, num=20)
y = (x)
y_int = integrate.cumtrapz(y, x, initial=0)
y_tr = np.trapz(y, x, axis = 0)
display(y_tr)
display(y_int)
Giving:
6.000000000000001
array([ 0. , -0.58171745, -1.06371191, -1.44598338, -1.72853186,
-1.91135734, -1.99445983, -1.97783934, -1.86149584, -1.64542936,
-1.32963989, -0.91412742, -0.39889197, 0.21606648, 0.93074792,
1.74515235, 2.65927978, 3.67313019, 4.7867036 , 6. ])
The result is 6 in each case.
Answered By - R Walser
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