Issue
I am getting the error after adding the URL in the home.html file. I migrated before running the program. I used commands to migrate. i.e., python manage.py migrate. 2. python manage.py makemigrations app_name. Django version I am using is 4.0.6. Thank you
Settings.py
from pathlib import Path
import os
# Build paths inside the project like this: BASE_DIR / 'subdir'.
BASE_DIR = Path(__file__).resolve().parent.parent
TEMPLATES_DIR=os.path.join(BASE_DIR,"templates")
# Quick-start development settings - unsuitable for production
# See https://docs.djangoproject.com/en/4.0/howto/deployment/checklist/
# SECURITY WARNING: keep the secret key used in production secret!
SECRET_KEY = 'django-insecure-d4@4fwcpkk$6a8ylqjmyhp-9%22t^aizetygwkxzw9s_wu5$&2'
# SECURITY WARNING: don't run with debug turned on in production!
DEBUG = True
ALLOWED_HOSTS = []
# Application definition
INSTALLED_APPS = [
'django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.messages',
'django.contrib.staticfiles',
'g6app',
]
MIDDLEWARE = [
'django.middleware.security.SecurityMiddleware',
'django.contrib.sessions.middleware.SessionMiddleware',
'django.middleware.common.CommonMiddleware',
'django.middleware.csrf.CsrfViewMiddleware',
'django.contrib.auth.middleware.AuthenticationMiddleware',
'django.contrib.messages.middleware.MessageMiddleware',
'django.middleware.clickjacking.XFrameOptionsMiddleware',
]
ROOT_URLCONF = 'g6.urls'
TEMPLATES = [
{
'BACKEND': 'django.template.backends.django.DjangoTemplates',
'DIRS': [TEMPLATES_DIR,],
'APP_DIRS': True,
'OPTIONS': {
'context_processors': [
'django.template.context_processors.debug',
'django.template.context_processors.request',
'django.contrib.auth.context_processors.auth',
'django.contrib.messages.context_processors.messages',
],
},
},
]
urls.py
from django.contrib import admin
from django.urls import path
from g6app.views import V1,V2
urlpatterns = [
path('admin/', admin.site.urls),
path("",V1.as_view(),name="v11"),
path("index/<int:pk>",V2.as_view(),name="index_detail1"),
]
admin.py
from django.contrib import admin
from . models import T1
# Register your models here.
admin.site.register(T1)
models.py
from django.db import models
from django.urls import reverse
# Create your models here.
class T1(models.Model):
name=models.CharField(max_length=100)
address=models.TextField()
def __str__(self):
return self.name
def get_absolute_url(self):
return reverse("index_detail",kwargs={"pk": self.pk})
views.py
from django.shortcuts import render
from django.views.generic import ListView, DetailView
from .models import T1
# Create your views here.
class V1(ListView):
model=T1
context_object_name="con1"
template_name="home.html"
class V2(DetailView):
model=T1
context_object_name="con2"
template_name="index_detail.html"
home.html
<!DOCTYPE HTML>
<html>
<head>
<meta charset="utf-8">
<title></title>
</head>
<body>
<h1>home page</h1>
{% block context %}
{% for T1 in con1 %}
<h4><a href="{% url 'index_detail' %}">{{T1.name}}</a></h4>
<h4>{{T1.address}}</h4>
{% endfor %}
{% endblock context %}
</body>
</html>
index_detail.html
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title></title>
</head>
<body>
<h1>detail view page</h1>
{% block context %}
{% for T1 in con2%}
<h4>{{T1.name}}</h4>]
<h4>{{T1.address}}</h4>
{% endfor %}
{% endblock context %}
</body>
</html>``
Solution
In your home.html you are trying to use this link:
<h4><a href="{% url 'index_detail' %}">{{T1.name}}</a></h4>
But in your urls.py you have:
path("index/<int:pk>",V2.as_view(),name="index_detail1"),
you need to change your path in urls.py to be same name as in your home.html.
path("index/<int:pk>",V2.as_view(),name="index_detail"),
Answered By - oruchkin
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