Issue
I have a list (in a dataframe) that looks like this:
oddnum = [1, 3, 5, 7, 9, 11, 23]
I want to create a new list that looks like this:
newlist = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 23]
I want to test if the distance between two numbers is 2 (if oddnum[index+1]-oddnum[index] == 2)
If the distance is 2, then I want to add the number following oddnum[index] and create a new list (oddnum[index] + 1)
If the distance is greater than two, keep the list as is
I keep getting key error because (I think) the list runs out of [index] and [index+1] no longer exists once it reaches the end of the list. How do I do this?
Solution
To pass errors, the best method is to use try
and except
conditions. Here's my code:
oddnum = [1, 3, 5, 7, 9, 11, 23]
res = [] # The new list
for i in range(len(oddnum)):
res.append(oddnum[i]) # Append the first value by default
try: # Tries to run the code
if oddnum[i] + 2 == oddnum[i+1]: res.append(oddnum[i]+1) # Appends if the condition is met
except: pass # Passes on exception (in our case KeyError)
print(res)
Answered By - The Myth
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