Issue
How can I concatenate two different model query and order by a field that both models has like progress fields.
For example
models.py
class Gig(models.Model):
author= models.ForeignKey(User)
title = models.CharFields()
progress = models.IntegerField()
class Project(models.Model):
author= models.ForeignKey(User)
title = models.CharFields()
progress = models.IntegerField()
Can I do my view.py like this, for me to achieve it?
İf No, How can I achieve it?
views.py
def fetch_all_item(request):
gig = Gig.objects.filter(author_id = request.user.id)
project = Project.objects.filter(author_id = request.user.id)
total_item = (gig + project).order_by("progress")
return render(request, "all_product.html", {"item": total_item})
I am trying to join two query set from Gig and Project models then send it to frontend in an ordering form by a field name called progress.
Solution
You can let Python do the sorting for you, like:
from operator import attrgetter
def fetch_all_item(request):
gig = Gig.objects.filter(author=request.user)
project = Project.objects.filter(author=request.user)
total_item = sorted([*gig, *project], attrgetter('progress'))
return render(request, "all_product.html", {'item': total_item})
It might however be better to remodel this to a single model with a type
field that disambiguates between a Gig
and a Project
.
Note: It is normally better to make use of the
settings.AUTH_USER_MODEL
[Django-doc] to refer to the user model, than to use theUser
model [Django-doc] directly. For more information you can see the referencing theUser
model section of the documentation.
Answered By - Willem Van Onsem
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