Issue
I would like to reverse a grouped data and use group name as xtick label to draw it side by side. below demo mostly good but the label position not as expected.
import pandas as pd
import matplotlib.pyplot as plt
import numpy as np
def main():
data = [['AAAAAA',8],['AAAAAA',9],['AAAAAA',10],['BBBBBB',5],['BBBBBB',6],['BBBBBB',7],['CCCCCC',1],['CCCCCC',2],['CCCCCC',3],['CCCCCC',4]]
df = pd.DataFrame(data,columns=['name','value'])
dfg = df.groupby('name')
fig, ax = plt.subplots(figsize=(8, 4))
i = 0
ymin = df['value'].min()
c1='#ececec'
c2='#bcbcbc'
color=c1
for ix, row in reversed(tuple(dfg)):
print(ix,row)
n = len(row['name'])
x = np.linspace(i,i + n,n)
ax.stem(x,row['value'])
font_dict = {'family':'serif','color':'darkred', 'size':8}
ax.text(i + n/2,ymin,ix,ha='right',va='top',rotation=90, fontdict=font_dict)
if color == c1:
color = c2
else:
color = c1
plt.axvspan(i, i+n, facecolor=color, alpha=0.5)
i += len(row)
ax.xaxis.set_ticks_position('none')
plt.setp( ax.get_xticklabels(), visible=False)
ax.grid(axis='y',color='gray', linestyle='dashed', alpha=1)
ax.spines[["top", "right"]].set_visible(False)
fig.tight_layout()
plt.show()
return
main()
Welcome to comment any other proper way to do this, or how to improve the xticks down, use ymin properly not good way to do it.
Solution
If my understanding of what you are trying to achieve is correct, here is one way to do it:
import numpy as np
import pandas as pd
from matplotlib import pyplot as plt
df = pd.DataFrame(
[
["AAAAAA", 8],
["AAAAAA", 9],
["AAAAAA", 10],
["BBBBBB", 5],
["BBBBBB", 6],
["BBBBBB", 7],
["CCCCCC", 1],
["CCCCCC", 2],
["CCCCCC", 3],
["CCCCCC", 4],
],
columns=["name", "value"],
)
fig, ax = plt.subplots(figsize=(8, 4))
i = 0
c1 = "#ececec"
c2 = "#bcbcbc"
color = c1
ticks = {}
for ix, row in reversed(tuple(df.groupby("name"))):
# Create stem plot
n = len(row["name"])
x = np.linspace(i, i + n, n)
ax.stem(x, row["value"])
# Create axvspan plot
if color == c1:
color = c2
else:
color = c1
ax.axvspan(i, i + n, facecolor=color, alpha=0.5)
# Save positions and names in a dict
for key, name in zip(x, row["name"]):
if key not in ticks.keys():
ticks[key] = name
else:
# Deal with multiple names for same tick
ticks[key] += f"\n{name}"
i += len(row)
# Add ticks and ticks labels
ax.set_xticks(ticks=list(ticks.keys()))
ax.set_xticklabels(list(ticks.values()), fontsize=10, rotation="vertical")
# In Jupyter notebook
fig
Output:
And to avoid repeating the labels, you can, for instance, do:
ax.set_xticklabels(
[
"",
"CCCCCC",
"",
"CCCCCC\nBBBBBB",
"BBBBBB",
"BBBBBB\nAAAAAA",
" " * 20 + "AAAAAA",
"",
],
fontsize=10,
)
# In Jupyter notebook
fig
Output:
Answered By - Laurent
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