[FIXED] Read line seperated by space using python using stdin

Issue

I want to be able to write a size for a input and after that enter each number seperated by space which is less or equal than the size.

Like this:

First input (length): 3

inputs: 1 2 3

This should also be converted as an integer and stored in a list

I have tried this:

import sys


inputs = sys.stdin.readline()

print(len(inputs))

mynumbers = inputs.strip().split(' ')

newlist = [int(x) for x in mynumbers]

print(newlist)

#print(input.rstrip(''))

Solution

Without using of stdin

A first possible answer (without use of stdin but using input) could be:

size = int(input("First input (length): "))
print(size)
input_value = input("inputs (length): ")
mynumbers = input_value.strip().split(' ')
newlist = [int(x) for x in mynumbers[:size]]
print(newlist)

Using stdin

print("First input (length): ")
inputs = sys.stdin.readline()
print("inputs: ")
input_value = sys.stdin.readline()
mynumbers = input_value.strip().split(' ')

# in new_list are inserted elements up to inputs value
newlist = [int(x) for x in mynumbers[0:(int)(inputs)]]

print(newlist)

In this case the output is:

First input (length): 
3
inputs: 
1 2 3 4
[1, 2, 3]

As you can see in the example I have selected 3 as length of the list, but I have inserted 4 elements.
In the list newlist there are only 3 elements because length==3.

Answered By - frankfalse