Issue
I have a large DataFrame with 100 million records, I am trying to optimize the run time by using numpy
.
Sample data:
dat = pd.DataFrame({'ID' : [1,2,3,4,5],
'item' : ['beauty', 'beauty', 'shoe','shoe','handbag'],
'mylist' : [['beauty','something'], ['shoe', 'something', 'else'], ['shoe', 'else','some'], ['else'], ['some', 'thing', 'else']]})
dat
ID item mylist
0 1 beauty [beauty, something]
1 2 beauty [shoe, something, else]
2 3 shoe [shoe, else, some]
3 4 shoe [else]
4 5 handbag [some, thing, else]
I am trying to filter those rows where item
column's string exists in mylist
column using:
dat[np.where(dat['item'].isin(dat['mylist']), True, False)]
But I am not getting any output and all of above values as False
.
I could get the required results using:
dat[dat.apply(lambda row : row['item'] in row['mylist'], axis = 1)]
ID item mylist
0 1 beauty [beauty, something]
2 3 shoe [shoe, else, some]
But as numpy
operations are faster, I am trying to use np.where
. Could someone please let me know who to fix the code?
Solution
You can't vectorize easily with Series of lists, you can use a list comprehension to be a bit faster than apply
:
out = dat.loc[[item in l for item,l in zip(dat['item'], dat['mylist'])]]
A vectorial solution would be:
out = dat.loc[dat.explode('mylist').eval('item == mylist').groupby(level=0).any()]
# or
out = dat.explode('mylist').query('item == mylist').groupby(level=0).first()
# or, if you are sure that there is at most 1 match
out = dat.explode('mylist').query('item == mylist')
But the explode
step might be a bottleneck. You must try with your real data.
output:
ID item mylist
0 1 beauty [beauty, something]
2 3 shoe [shoe, else, some]
timing
I ran a quick test on 100k rows (using df = pd.concat([dat]*20000, ignore_index=True)
)
- the list comprehension is the fastest (~20ms)
- explode approaches are between 60-90ms (explode itself requiring 40ms)
- apply is by far the slowest (almost 600ms)
Answered By - mozway
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