[FIXED] Remove items at given positions from a list

Issue

I am having difficulty finding a solution to my problem. I need to remove [4,1] from [4,4,4,1,1] and [5,2] from [5,5,2,2,1], only at their first occurrence. The desired result should be [4,4,1] and [5,2,1]. I appreciate your help. Thank you.

Solution

I made a function which is much simpler. This is similar to competitive programming. So from your question, it looks like, the default is the first number, then when a new number comes, it removes it and the previous number before it. code:

#arr is array
def convert(arr):
    default =arr[0]
    for i in range(len(arr)):
        if arr[i] != default:
            arr.pop(i)
            arr.pop(i-1)
            break
    print(arr)
#put your list inside the function
#convert()
#example
convert([4,4,4,1,1])
convert([5,5,5,2,2])

Answered By - Blazing Star