[FIXED] Start and stop audio streaming using http or mqtt calls - Python

Issue

I have a python script that streams audio. It uses websockets, asyncio and pyaudio. I want to start and stop streaming or this complete script with HTTP or MQTT call. Currently what I am doing manually i.e. To Start : python script.py To Stop : Ctrl C

What approach shall I use?

# starts recording
stream = p.open(
   format=FORMAT,
   channels=CHANNELS,
   rate=RATE,
   input=True,
   frames_per_buffer=FRAMES_PER_BUFFER
)

async def send_receive():
   print(f'Connecting websocket to url ${URL}')
   async with websockets.connect(
       URL,
       extra_headers=(("Authorization", auth_key),),
       ping_interval=5,
       ping_timeout=20
   ) as _ws:
       await asyncio.sleep(0.1)
       print("Receiving SessionBegins ...")
       session_begins = await _ws.recv()
       print(session_begins)
       print("Sending messages ...")
       async def send():
           while True:
               try:
                   data = stream.read(FRAMES_PER_BUFFER)
                   data = base64.b64encode(data).decode("utf-8")
                   json_data = json.dumps({"audio_data":str(data)})
                   await _ws.send(json_data)
               except websockets.exceptions.ConnectionClosedError as e:
                   print(e)
                   assert e.code == 4008
                   break
               except Exception as e:
                   assert False, "Not a websocket 4008 error"
               await asyncio.sleep(0.01)

           return True

       async def receive():
           while True:
               try:
                   result_str = await _ws.recv()
                   print(json.loads(result_str)['text'])
               except websockets.exceptions.ConnectionClosedError as e:
                   print(e)
                   assert e.code == 4008
                   break
               except Exception as e:
                   assert False, "Not a websocket 4008 error"

       send_result, receive_result = await asyncio.gather(send(), receive())


asyncio.run(send_receive())

Solution

To start and stop a Python script using an HTTP call, you can set up a web server that listens for specific requests to trigger the execution or termination of your script. Here's a basic example using the Flask framework:

Install Flask:

pip install flask

Create a new Python file, e.g., script_controller.py, and import the necessary modules:

from flask import Flask, request
import subprocess

app = Flask(__name__)
process = None

Define route handlers for starting and stopping the script:

@app.route('/start_script', methods=['POST'])
def start_script():
    global process
    if process is None or process.poll() is not None:
        # Start the script if it's not already running
        process = subprocess.Popen(['python', 'your_script.py'])
        return 'Script started successfully.'
    else:
        return 'Script is already running.'

@app.route('/stop_script', methods=['POST'])
def stop_script():
    global process
    if process and process.poll() is None:
        # Terminate the script if it's running
        process.terminate()
        return 'Script stopped successfully.'
    else:
        return 'Script is not running.'

if __name__ == '__main__':
    app.run()

Replace 'your_script.py' in the start_script route handler with the filename of the script you want to execute.

Start the web server by running the script_controller.py file:

python script_controller.py

Once the server is running, you can send HTTP requests to start or stop the script:

To start the script:

POST http://localhost:5000/start_script

To stop the script:

POST http://localhost:5000/stop_script

Answered By - Abhishek Kumar