[FIXED] How to convert independent bytes to bytearray?

Issue

Iam receiving single bytes via serial and I know, that every 4 of them are a float. F.e. I receive b'\x3c' and b'\xff' and I want it to be b'\x3c\xff'. What is the best way to convert it?

Solution

You can use join() as you do with strings.

byte_1 = b'\x3c'
byte_2 = b'\xff'

joined_bytes = b''.join([byte_1, byte_2]) #b'\x3c\xff'

You can use it along the struct module to obtain your decoded float, be aware it returns a tuple even if it has only one element inside.

import struct

byte_1 = b'\x3c'
byte_2 = b'\xff'
byte_3 = b'\x20'
byte_4 = b'\xff'

joined_bytes = b''.join([byte_1, byte_2, byte_3, byte_4])

result = struct.unpack('f', joined_bytes)
print(result[0])

Answered By - Raulillo