Issue
suppose I have an array of shape (2,2,3): x=np.array([[[1,2,3],[4,5,6]],[[7,8,9],[10,11,12]]])
, and I have transposed this array to y along axes (2,0,1): y=np.transpose(x,(2,0,1))
.
My questions is, how to transpose y back to x? I know I can use np.transpose(y,(1,2,0))
to change back to x, but I'd like to have a neat way of finding that correct axes (1,2,0).
Thanks for any help!
Solution
You can use
np.argsort((2, 0, 1))
It gives:
array([1, 2, 0])
It will work with any permutation of axes.
Answered By - bb1
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