[FIXED] Redirect to named url pattern directly from urls.py in django?

Issue

In Django, how can I do a simple redirect directly from urls.py? Naturally I am a well organized guy, favoring the DRY principle, so I would like to get the target based on it's named url pattern, rather than hard coding the url.

Solution

You can use RedirectView.

If you are on Django 1.4 or 1.5, you can do this:

from django.core.urlresolvers import reverse_lazy
from django.views.generic import RedirectView

urlpatterns = patterns('',
    url(r'^some-page/$', RedirectView.as_view(url=reverse_lazy('my_named_pattern'), permanent=False)),
    ...

If you are on Django 1.6 or above, you can do this:

from django.views.generic import RedirectView

urlpatterns = patterns('',
    url(r'^some-page/$', RedirectView.as_view(pattern_name='my_named_pattern', permanent=False)),
    ...

In Django 1.9, the default value of permanent has changed from True to False. Because of this, if you don't specify the permanent keyword argument, you may see this warning:

RemovedInDjango19Warning: Default value of 'RedirectView.permanent' will change from True to False in Django 1.9. Set an explicit value to silence this warning.

Answered By - thnee