Issue
I am trying to get data of all the Amazon bestseller and to process that i have used the scrapy, i am able to get the whole selector list of data yet while iterating over the data list the result is still returning only single data item.
def parse_page(self, response):
product_data = response.xpath("//div[@id='gridItemRoot']") #THIS RETURNS A SELECTOR LIST
for data in product_data:
product_name = data.xpath("//div[@class='a-section a-spacing-mini _cDEzb_noop_3Xbw5']//img/@alt").get()
product_rank = data.xpath("//span[@class='zg-bdg-text']/text()").get()
# It only generates a single result
yield {
"name": product_name,
"rank": product_rank
}
i tried without iterating over a selectorlist rather passing selector directly to the method and yielding result but that also returned a single element.
def parse_page(self, response):
# in previous applications all the results were scraped without iterating over any selectorlist just like following
product_name = response.xpath("//div[@class='a-section a-spacing-mini _cDEzb_noop_3Xbw5']//img/@alt").get()
product_rank = response.xpath("//span[@class='zg-bdg-text']/text()").get()
yield {
"name": product_name,
"rank": product_rank
}
Solution
You need to use relative xpath expressions.
def parse_page(self, response):
product_data = response.xpath("//div[@id='gridItemRoot']") #THIS RETURNS A SELECTOR LIST
for data in product_data:
product_name = data.xpath(".//div[@class='a-section a-spacing-mini _cDEzb_noop_3Xbw5']//img/@alt").get()
product_rank = data.xpath(".//span[@class='zg-bdg-text']/text()").get()
# It only generates a single result
yield {
"name": product_name,
"rank": product_rank
}
Without the .
at the beginning of the xpath expression it will always grab the first match relative to the root element, which will always be the same element for every iteration.
Answered By - Alexander
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