Issue
I am trying to use Mateplotlib cartopy to make the plots below. Here is the code that I am using.
import cartopy.crs as ccrs
fig=plt.figure(figsize=(15,11))
ax = plt.subplot(111, projection=ccrs.PlateCarree(central_longitude=0))
mm = ax.contourf(new_lon[:],lat_post,new_aa[0,:,:],transform=ccrs.PlateCarree(central_longitude=0))
ax.coastlines(resolution='10m');
ax.stock_img();
# the following two lines increaes the vertical distance between the title and the upper tick.
from matplotlib import rcParams
rcParams['axes.titlepad']=20
# drawing the longitude and latitude ticks.
gl = ax.gridlines(crs=ccrs.PlateCarree(central_longitude=0), draw_labels=True,linewidth=2, color='gray', alpha=0.5, linestyle='--')
Yet, once I add the following code set_extent
ax.set_extent([np.min(new_lon),np.max(new_lon),np.min(lat_post)
,np.max(lat_post)])
Solution
Looking at your original map, it looks like there's a seam at 0 longitude, so I'm guessing np.min(new_lon)
is 0, and np.min(new_lon)
is 360. If you use that with set_extent()
, you're getting a really narrow strip at the prime meridian. I'm guess if you do set_extent([-180, 180, ,np.min(lat_post), np.max(lat_post)]
it will work better.
The only way I can think of to achieve it programmatically in this case is to do:
lon_bounds = new_lon[:] # copy
lon_bounds[lon_bounds > 180] -= 360
ax.set_extent([np.min(lon_bounds), np.max(lon_bounds), np.min(lat_post), np.max(lat_post)])
Answered By - DopplerShift
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