[FIXED] How do I check if a numpy dtype is integral?

Issue

How do I check if a numpy dtype is integral? I tried:

issubclass(np.int64, numbers.Integral)

but it gives False.

---

Update: it now gives True.

Solution

Numpy has a hierarchy of dtypes similar to a class hierarchy (the scalar types actually have a bona fide class hierarchy that mirrors the dtype hierarchy).

In Numpy>2.0, you should use np.isdtype: np.isdtype(np.void, 'integral').

Otherwise, you can use np.issubdtype(some_dtype, np.integer) to test if a dtype is an integer dtype. Note that like most dtype-consuming functions, np.issubdtype() will convert its arguments to dtypes, so anything that can make a dtype via the np.dtype() constructor can be used.

http://docs.scipy.org/doc/numpy/reference/arrays.dtypes.html#specifying-and-constructing-data-types

>>> import numpy as np
>>> np.issubdtype(np.int32, np.integer)
True
>>> np.issubdtype(np.float32, np.integer)
False
>>> np.issubdtype(np.complex64, np.integer)
False
>>> np.issubdtype(np.uint8, np.integer)
True
>>> np.issubdtype(np.bool, np.integer)
False
>>> np.issubdtype(np.void, np.integer)
False

Alternatively, the scalar types are now registered with the appropriate numbers ABCs.

Answered By - Robert Kern