[FIXED] How to set timeout to pyplot.show() in matplotlib?

Issue

I am using python's matplotlib to draw figures.

I want to draw a figure with a timeout, say 3 seconds, and the window will close to move on the code.

I have known that pyplot.show() will create a blocking window with unlimited timeout; pyplot.show(block=False) or pyplot.draw() will make the window non-blocking. But what I want is let the code block for some seconds.

I have come up an idea that I might use an event handler or something, but still not really clear how to solve this. Is there any simple and elegant solution?

Suppose my code is like the following:

Draw.py:

import matplotlib.pyplot as plt

#Draw something
plt.show() #Block or not?

Solution

Here's a simple example where I have created a timer to set your timeout and performed closing of window plot.close() in the callback function of the timer. Start the timer before plot.show() and after three seconds timer invokes close_event() and then continues with the rest of the code.

import matplotlib.pyplot as plt

def close_event():
    plt.close() #timer calls this function after 3 seconds and closes the window 

fig = plt.figure()
timer = fig.canvas.new_timer(interval = 3000) #creating a timer object and setting an interval of 3000 milliseconds
timer.add_callback(close_event)

plt.plot([1,2,3,4])
plt.ylabel('some numbers')

timer.start()
plt.show()
print("I am doing something else")

Hope that was helpful.

Answered By - Deepa