[FIXED] How to simplify this python expression?

Issue

numpy.concatenate((a0,a1,a2,a3,a4,a5,a6,a7,a8,a9,a10,a11,a12,a13,a14,a15,a16,a17,a18,a19,a20,a21,a22,a23,a24,a25,a26,a27,a28,a29,a30,a31,a32,a33,a34,a35,a36,a37,a38,a39,a40,a41,a42,a43,a44,a45,a46,a47,a48,a49,a50,a51,a52,a53,a54,a55,a56,a57,a58,a59,a60,a61,a62,a63,a64,a65,a66,a67,a68,a69,a70,a71,a72,a73,a74,a75,a76,a77,a78,a79,a80,a81,a82,a83,a84,a85,a86,a87,a88,a89,a90,a91,a92,a93,a94,a95,a96,a97,a98,a99,a100,a101,a102,a103,a104,a105,a106,a107,a108,a109,a110,a111,a112,a113,a114,a115,a116,a117,a118,a119,a120,a121,a122,a123,a124,a125,a126,a127,a128,a129,a130,a131,a132,a133,a134,a135,a136,a137,a138,a139,a140,a141,a142,a143,a144,a145,a146,a147,a148,a149,a150,a151,a152,a153,a154,a155,a156,a157,a158,a159,a160,a161,a162,a163,a164,a165,a166,a167,a168,a169,a170,a171,a172,a173,a174,a175,a176,a177,a178,a179,a180,a181,a182,a183,a184,a185,a186,a187,a188,a189,a190,a191,a192,a193,a194,a195,a196,a197,a198,a199,a200,a201,a202,a203,a204,a205,a206,a207,a208,a209,a210,a211,a212,a213,a214,a215,a216,a217,a218,a219,a220,a221,a222,a223,a224,a225,a226,a227,a228,a229,a230,a231,a232,a233)) 

a0 to a233 are array names which have been defined and assigned values to.

Solution

As i understand you want to create all the array names (a0 to a233) that you needed to concatenate in order to make the code shorten

If that's the case you can use list comprehension and f-strings without manually typing each name:

array_names = [f"a{i}" for i in range(234)]  # Create names a0 to a233

now you've a list of arrays:

>>> print(array_names)
['a0', 'a1', 'a2', ..., 'a232', 'a233']

you can use expression:

np.concatenate([globals()[f"a{i}"] for i in range(234)])

you can also use np.vstack for faster vertical concatenation:

np.vstack([globals()[f"a{i}"] for i in range(234)])

Answered By - Rashid ur Rehman