[FIXED] Ipywidgets interactive - take a dictionary as an argument

Issue

I have a function that looks like this that takes a dictionary as an argument. The dictionary looks like this:

d = {'skill_1':3, 'skill_2':2, 'skill_5':5, 'skill_7':3}

The function i have is a function that takes this dictionary, and then looks into a dataframe for the people that have a value greater or equal that the one in the dictionary, for the skills mentioned. It looks like this:

   skill_0  skill_1  skill_2  skill_3  skill_4  skill_5  skill_6  skill_7  
0        5        3        1        4        2        3        4        2   
1        3        2        1        3        2        2        5        1   
2        3        1        3        3        3        1        3        4   
3        3        5        4        5        5        5        3        3   
4        5        4        3        2        4        3        4        1   

I want to receive this argument from a widget(or using 2 widgets and then combining the values of the two widgets into a dictionary).

I have tried something like

s = ['skill_0', 'skill_1', 'skill_2', 'skill_3', 'skill_4', 'skill_5', 'skill_6', 'skill_7']
widgets.SelectMultiple(options=[f'{i}:{n}' for i in s for n in range(1,6)], value=('skill_3:1',))

But i cant manage to retrive the value from the widget and make a dictionary (i tried with eval too.). Also, the list like this looks visually ugly. Is there any way to achieve this?

Solution

Attempt to read the widget List from ipywidgets and specially the observe section. You can made a HBox (Horizontal Box) with a VBox (Vertical Box), in the vertical, create a Label and the Selector that you want, observe when selector change to automatic change values to dict with de function, like this:

import ipywidgets as widgets
from functools import partial
s = ['skill_0', 'skill_1', 'skill_2', 'skill_3', 'skill_4', 'skill_5', 'skill_6', 'skill_7']

values = {}
def update_value(label, widget):
    values[label.value] = widget.new
    print(values)

horizontal = []
for skill in range(7):
    title = widgets.Label(f"skill_{skill}")
    multiple = widgets.Select(options=[n for n in range(0, 5)])
    multiple.observe(partial(update_value, title), names=["value"], type="change")
    new_vertical = widgets.VBox([title, multiple])
    horizontal.append(new_vertical)

line = widgets.HBox(horizontal)
display(line)

Answered By - Sergio Gao