Issue
I'm plotting a 3d bar plot for an array using matplotlib. I need to add an edgecolor to the bars. However, the edgecolor is coloring the 0.0 values data points in black. Is there a way to not color these data points? I'm trying to do edgecolors=none through a loop when values are 0.0. However this doesn't seem to help. Any help appreciated.
The script I use to plot,
from mpl_toolkits.mplot3d import Axes3D
fig = plt.figure()
ax = Axes3D(fig)
lx= len(r[0])
ly= len(r[:,0])
xpos = np.arange(0,lx,1)
ypos = np.arange(0,ly,1)
xpos, ypos = np.meshgrid(xpos+0.25, ypos+0.25)
xpos = xpos.flatten()
ypos = ypos.flatten()
zpos = np.zeros(lx*ly)
cs = ['r', 'g', 'b', 'y', 'c'] * ly
edgecolor_store = []
dx = 0.5 * np.ones_like(zpos)
dy = 0 * np.ones_like(zpos)
#dz = zpos
dz = r.flatten()
for value in dz:
if value == 0.0:
edgecolor_store.append('none')
if value > 0.0:
edgecolor_store.append('black')
mask_dz = dz == 0 # SO:60111736, 3d case
#print(dz)
ax.bar3d(xpos,ypos,zpos, dx, dy,dz,color=cs,zsort='average',alpha=0.5,edgecolors=edgecolor_store)
Sample data I use,
[ 0. , 0. , 0. , 0. , 0. ],[ 0. , 0. , 0. , 0. , 0. ],[ 0. , 0. , 0. , 0. , 0. ],[ 0. , 0. , 0. , 0. , 0. ],[ 0. , 0. , 0. , 0. , 0. ],[ 0. , 0. , 0. , 0. , 0. ],[ 0. , 0. , 20.7, 0. , 0. ],[ 0.6, 0. , 0.1, 0. , 0.2],[ 0. , 24.8, 0. , 46.7, 0. ],[ 0. , 0. , 99.7, 17.1, 99.3],[ 0. , 12.8, 98.6, 0. , 6.7],[ 0.2, 0. , 0. , 12.6, 0. ]
The output plot I get is,
Solution
I feel that you've already tried the correct solution: not plot the unwanted bars.
You need a mask. Btw, never ever compare floats with ==
.
mask = ~np.isclose(dz, 0.0)
Then, plot data filtered by this mask
ax.bar3d(xpos[mask],ypos[mask],zpos[mask], dx[mask], dy[mask],dz[mask],color=cs[:mask.sum()],zsort='average',alpha=0.5,edgecolors='black')
Note that you no longer need edgecolor. And that my way of computing cs
(starting from your too long cs
, and truncating it to the exact needed size) is not optimal.
Also note that the 4 remaining black lines are not 0, but very small (0.1, 0.2, 0.2 and 0.6) values.
Answered By - chrslg
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