[FIXED] pandas concat generates nan values

Issue

I am curious why a simple concatenation of two dataframes in pandas:

initId.shape                # (66441, 1)
initId.isnull().sum()       # 0

ypred.shape                 # (66441, 1)
ypred.isnull().sum()        # 0

of the same shape and both without NaN values

foo = pd.concat([initId, ypred], join='outer', axis=1)
foo.shape                   # (83384, 2)
foo.isnull().sum()          # 16943

can result in a lot of NaN values if joined.

How can I fix this problem and prevent NaN values being introduced? Trying to reproduce it like

aaa  = pd.DataFrame([0,1,0,1,0,0], columns=['prediction'])
bbb  = pd.DataFrame([0,0,1,0,1,1], columns=['groundTruth'])
pd.concat([aaa, bbb], axis=1)

failed e.g. worked just fine as no NaN values were introduced.

Solution

I think there is problem with different index values, so where concat cannot align get NaN:

aaa  = pd.DataFrame([0,1,0,1,0,0], columns=['prediction'], index=[4,5,8,7,10,12])
print(aaa)
    prediction
4            0
5            1
8            0
7            1
10           0
12           0

bbb  = pd.DataFrame([0,0,1,0,1,1], columns=['groundTruth'])
print(bbb)
   groundTruth
0            0
1            0
2            1
3            0
4            1
5            1

print (pd.concat([aaa, bbb], axis=1))
    prediction  groundTruth
0          NaN          0.0
1          NaN          0.0
2          NaN          1.0
3          NaN          0.0
4          0.0          1.0
5          1.0          1.0
7          1.0          NaN
8          0.0          NaN
10         0.0          NaN
12         0.0          NaN

Solution is reset_index if indexes values are not necessary:

aaa.reset_index(drop=True, inplace=True)
bbb.reset_index(drop=True, inplace=True)

print(aaa)
   prediction
0           0
1           1
2           0
3           1
4           0
5           0

print(bbb)
   groundTruth
0            0
1            0
2            1
3            0
4            1
5            1

print (pd.concat([aaa, bbb], axis=1))
   prediction  groundTruth
0           0            0
1           1            0
2           0            1
3           1            0
4           0            1
5           0            1

EDIT: If need same index like aaa and length of DataFrames is same use:

bbb.index = aaa.index
print (pd.concat([aaa, bbb], axis=1))
    prediction  groundTruth
4            0            0
5            1            0
8            0            1
7            1            0
10           0            1
12           0            1

Answered By - jezrael