Issue
I have a TF Dataset with the following schema:
tf_features = {
'searched_destination_id': tf.io.FixedLenFeature([], tf.int64, default_value=0),
'booked_acc_id': tf.io.FixedLenFeature([], dtype=tf.int64, default_value=0),
'user_id': tf.io.FixedLenFeature([], dtype=tf.int64, default_value=0),;
}
I also have a dict like:
candidates = {'111': [123, 444, ...], '222': [555, 888, ...]...}
I'd like to perform a map operation in the following way:
ds.map(lambda x, y: {**x, 'candidates': candidates[x['searched_destination_ufi'].numpy()]})
However I always get: AttributeError: 'Tensor' object has no attribute 'numpy'
when I remove the .numpy()
I get TypeError: Tensor is unhashable. Instead, use tensor.ref() as the key.
Do you suggest any solution?
Solution
The function dataset.map
works in graph mode, where calling .numpy()
on a tensor is not possible. You could try using tf.py_function
to include the candidates dict
into your dataset:
import tensorflow as tf
tf_features = {
'searched_destination_ufi': ['111', '222'],
'booked_hotel_ufi': [2, 4],
'user_id': [3, 2]
}
ds = tf.data.Dataset.from_tensor_slices(tf_features)
candidates = {'111': [123, 444], '222': [555, 888]}
def py_func(x):
x = x.numpy().decode('utf-8')
return candidates[x]
ds = ds.map(lambda x: {**x, 'candidates': tf.py_function(py_func, [x['searched_destination_ufi']], [tf.int32]*2)})
for x in ds:
print(x)
{'searched_destination_ufi': <tf.Tensor: shape=(), dtype=string, numpy=b'111'>, 'booked_hotel_ufi': <tf.Tensor: shape=(), dtype=int32, numpy=2>, 'user_id': <tf.Tensor: shape=(), dtype=int32, numpy=3>, 'candidates': <tf.Tensor: shape=(2,), dtype=int32, numpy=array([123, 444], dtype=int32)>}
{'searched_destination_ufi': <tf.Tensor: shape=(), dtype=string, numpy=b'222'>, 'booked_hotel_ufi': <tf.Tensor: shape=(), dtype=int32, numpy=4>, 'user_id': <tf.Tensor: shape=(), dtype=int32, numpy=2>, 'candidates': <tf.Tensor: shape=(2,), dtype=int32, numpy=array([555, 888], dtype=int32)>}
Note that [tf.int32]*2
corresponds to the length of the lists in candidates
.
For a more sophisticated approach, you can use tf.lookup.StaticHashTable
and tf.gather
, which will both work in graph mode:
import tensorflow as tf
tf_features = {
'searched_destination_ufi': ['111', '222'],
'booked_hotel_ufi': [2, 4],
'user_id': [3, 2]
}
ds = tf.data.Dataset.from_tensor_slices(tf_features)
candidates = {'111': [123, 444], '222': [555, 888]}
keys = list(candidates.keys())
values = tf.constant(list(candidates.values()))
table = tf.lookup.StaticHashTable(
tf.lookup.KeyValueTensorInitializer(tf.constant(keys), tf.range(len(keys))),
default_value=-1)
ds = ds.map(lambda x: {**x, 'candidates': tf.gather(values, [table.lookup(x['searched_destination_ufi'])])})
for x in ds:
print(x)
{'searched_destination_ufi': <tf.Tensor: shape=(), dtype=string, numpy=b'111'>, 'booked_hotel_ufi': <tf.Tensor: shape=(), dtype=int32, numpy=2>, 'user_id': <tf.Tensor: shape=(), dtype=int32, numpy=3>, 'candidates': <tf.Tensor: shape=(1, 2), dtype=int32, numpy=array([[123, 444]], dtype=int32)>}
{'searched_destination_ufi': <tf.Tensor: shape=(), dtype=string, numpy=b'222'>, 'booked_hotel_ufi': <tf.Tensor: shape=(), dtype=int32, numpy=4>, 'user_id': <tf.Tensor: shape=(), dtype=int32, numpy=2>, 'candidates': <tf.Tensor: shape=(1, 2), dtype=int32, numpy=array([[555, 888]], dtype=int32)>}
If the candidates field is of variable length use a ragged tensor and the second approach, the rest of the code remains the same:
candidates = {'111': [123, 444], '222': [555, 888, 323]}
keys = list(candidates.keys())
values = tf.ragged.constant(list(candidates.values()))
{'searched_destination_ufi': <tf.Tensor: shape=(), dtype=string, numpy=b'111'>, 'booked_hotel_ufi': <tf.Tensor: shape=(), dtype=int32, numpy=2>, 'user_id': <tf.Tensor: shape=(), dtype=int32, numpy=3>, 'candidates': <tf.RaggedTensor [[123, 444]]>}
{'searched_destination_ufi': <tf.Tensor: shape=(), dtype=string, numpy=b'222'>, 'booked_hotel_ufi': <tf.Tensor: shape=(), dtype=int32, numpy=4>, 'user_id': <tf.Tensor: shape=(), dtype=int32, numpy=2>, 'candidates': <tf.RaggedTensor [[555, 888, 323]]>}
Answered By - AloneTogether
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