[FIXED] How can I increment items in a list alphabetically?

Issue

I have the following Python code that prints data based on a template.

In the template, each selection is preceded by empty brackets, like this:

-[ ] selection one
-[ ] selection two
-[ ] selection three

Is there a way to change my script so that it increments with letters?

Like:

a. selection one
b. selection two
c. selection three

I tried using something like s = bytes([ch[0] + 1]) but I kept encountering a bunch of errors.

Here is my script:

def __str__(self):
    # show the correct order (noted by Sarah)
    self.options.sort(key=attrgetter('order'))
    # make sure it supports multiple correct selections
    correct_selection = ", ".join([
        str(selection)
        for selection
        in self.options
        if selection.correct
    ])

    # also, make sure it substitutes only the known values (see Tompei for ?)
    return _TEMPLATE.safe_substitute({
        'dilemma_ethos': self.text,
        'options': "\n".join([f'-[ ] {option}' for option in self.options]),
        'correct_selection': correct_selection,
    })

Solution

This is an example of how you could do it assuming that the template is a string (but as noted it won't work beyond z)

template_1 = """-[ ] selection one
-[ ] selection two
-[ ] selection three"""

def convert(template):
    return '\n'.join([f"{chr(i + 97)}. {line[5:]}" for i, line in enumerate(template.split('\n'))])

print(convert(template_1))

This below does the same thing, but is easier to read:

template_1 = """-[ ] selection one
-[ ] selection two
-[ ] selection three"""

def convert(template):
    new_list = []
    template_list = template.split('\n')
    for count, line in enumerate(template_list):
        new_list.append(f"{chr(count + 97)}. {line[5:]}")
    separator = '\n'
    return separator.join(new_list)

print(convert(template_1))

The function returns with a string containing the converted template.

Answered By - Lee-xp