[FIXED] How do i break out of this while loop in Python?

Issue

def main():
  dmn_options = ["lenovo", "rasbberrypi", "Exit"]
  while True:
    display_menu(dmn_options)
    user_choice = select_single_l(dmn_options);print(user_choice)
    
  
def display_menu(options):
  print("Select an option:")
  for index, option in enumerate(options, start=1):
    print(f"{index}. {option}")

def select_single_l(options):
  choice=None
  while True:
    try:
      i = int(input("Enter the number of your choice: "))
      if 1 <= i <= len(options) - 1:
        choice=options[i - 1]
        print(f"You selected {choice}.")
        break
      elif i == len(options):
        print("Exiting the menu.")
        break
      else:
        print("Invalid choice. Please enter a valid number.")
    except ValueError:
      print("Invalid input. Please enter a number.")
    break
  return choice

I've tried chatGPT but to no avail. I tell the code to break but it does not break - it is frustrating. When the user select Exit it is meant to stop selecting - mimicking Bash's select statement. Please help.

Solution

Your issue stems from you not exiting your main() while loop

def main():
  dmn_options = ["lenovo", "rasbberrypi", "Exit"]
  while True:
    display_menu(dmn_options)
    user_choice = select_single_l(dmn_options);print(user_choice)

Here is an example doing so without altering your original code too much.

def main():
  dmn_options = ["lenovo", "rasbberrypi", "Exit"]
  while True:
    display_menu(dmn_options)
    user_choice = select_single_l(dmn_options);print(user_choice)
    if user_choice == None:
      break
    
  
def display_menu(options):
  print("Select an option:")
  for index, option in enumerate(options, start=1):
    print(f"{index}. {option}")

def select_single_l(options):
  choice=None
  while True:
    try:
      i = int(input("Enter the number of your choice: "))
      if 1 <= i <= len(options) - 1:
        choice=options[i - 1]
        print(f"You selected {choice}.")
        break
      elif i == len(options):
        print("Exiting the menu.")
        break
      else:
        print("Invalid choice. Please enter a valid number.")
    except ValueError:
      print("Invalid input. Please enter a number.")
    break
  return choice

Answered By - Annie Wannie