[FIXED] How to sort a dictionary from low to high in python?

Issue

I want to sort the values of this dictionary from low to high:

For example, input:

average = {'ali': 7.83, 'mahdi': 13.4, 'hadi': 16.2, 'hasan': 3.57}

I want the output to be like this:

{'hasan': 3.57, 'ali': 7.83, 'mahdi': 13.4, 'hadi': 16.2}

I tested this method, but because my data is decimal, it gives an error:

dict(sorted(average.items(), key=lambda item: item[1]))

Error:

ave_dict_sort = dict(sorted(average.items(), key=lambda item: item[1]))
                                ^^^^^^^^^^^^^
AttributeError: 'float' object has no attribute 'items'

Solution

You can use the sorted function along with a lambda function as the key to achieve this. Here's an example of how you can sort the dictionary by values in ascending order:

average = {'ali': 7.83, 'mahdi': 13.4, 'hadi': 16.2, 'hasan': 3.57}

sorted_average = dict(sorted(average.items(), key=lambda item: item[1]))

print(sorted_average)

This will output:

{'hasan': 3.57, 'ali': 7.83, 'mahdi': 13.4, 'hadi': 16.2}

Here, sorted(average.items(), key=lambda item: item[1]) sorts the dictionary items based on their values (item[1]), and dict() is used to convert the sorted items back into a dictionary.

Answered By - Zohair